If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5m-m^2=6
We move all terms to the left:
5m-m^2-(6)=0
We add all the numbers together, and all the variables
-1m^2+5m-6=0
a = -1; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·(-1)·(-6)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-1}{2*-1}=\frac{-6}{-2} =+3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+1}{2*-1}=\frac{-4}{-2} =+2 $
| 14=7x-9-x | | 5^(x+4)-5^(x+2)=24 | | 13t-7=-24 | | (x-45)+(x-45)+x+(x-45)+x=540 | | 0.5(4a−8)=22 | | 3n+6=n+8n | | 10x-12=8x+10 | | n^2+7n-14=0 | | -10y+10y+-2y=8 | | 5x-6x=5x+6 | | 4x+4x+12x=180 | | 32x+1=26x+2 | | 9p-3p-3p=15 | | 18t+5t+t-19t=20 | | 3x-5=9x-3 | | 15x=16x-7 | | 30x^2+40x=1 | | 17k−20k−-15k−-k−7k=-12 | | (a/3)+4=5 | | 11x+12=12x+; | | 95-n=0.06 | | 2(5b+6)=5(b-6) | | 120x+160=1 | | 2(-6+x)=x-2/3 | | 15z+2z-6z-8z-z=6 | | 6y+18=8y+36+4y | | 12s*12=60*12 | | 5(a-1)-15=2(a+2)+4 | | 16v-16v+5v+5v=20 | | 2(u-8)-8u=-22 | | 11z-9z=20 | | 12s*12=60 |